Physics, asked by lakkisharma331, 1 year ago

A mass of 1 kg is suspended from a spring. Its time period of oscillation on the earth is T. What will be its time period at the centre of the earth??

Answers

Answered by abhinav27122001
3

The time period will be T again as the time period of the oscillation of the spring does not depend on g.

T=2π√(m/k) where,

k is the spring constant and m is the mass suspended.

Answered by axbSnape
1

Answer:

T itself

Explanation:

At centre of earth g=0, how ever period of oscillation is given by

T=2π \sqrt{\frac{m}{k} }

m= mass (not weight)

k = spring constant

The above equation is independent of g Acceleration due to gravity.

so time period is T.

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