Question

a mass of 1 kg is suspended from a spring of stiffness constant 25 Newton / metre. If the undamped frequency is 2 by root 3 times the damped frequency ,calculate the damping factor
(answer should be 5kg/s)​

Answer 1

Answer:

The natural undamped frequency is given by

fn=2π1Mk⇒fn=2π1546000=15.26Hz

The damped frequency is given by

f=fn1−δ2=15.26×1−0.09=14.56Hz

Explanation:

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