A mass of 10 grams is connected to a massless spring then time period of a small of oscillation is 10 second.If 10 g mass is replaced by 40 g mass in same spring then its time period will be
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Answer:
Hy mate your answer is here
Explanation:
The time period will be T again as a time period of the oscillations of the spring does not depend on gram.
T=2π√(m/k) where,
K is the spring constant and m is the mass suspended.
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