Question

a mass of 10 kg connected to end of rod of negligible mass is rotating in a circle of radius 30 cm and angular velocity of 10 meter per second if the mass is brought to rest in 10 seconds what is the torque applied

Answer 1

torque = m r w/t . r
= 10 × 30×30/100×100
= 9000/10000
= 0.9