A mass of 10 kg is balanced on a sensitive physical balance.A 1000 kg mass is placed below 10 kg mass at a distance of 1m.how much additional mass will be required for balancing the physical balance
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Answer:
Using the Newton’s law of gravitation
F=GMmr2
F is the force between the two bodies
G is the gravitational constant
M is mass for first body
m is mass of second body
r is distance between two bodies
F=6.6×10−11×10×10001
F=6.6×10−7N
We know that,
F=mg
g is acceleration due to gravity
Therefore,
mg=6.6×10−7N
m=6.7×10−8kg
The additional mass will be required for balancing the physical balance is 6.7×10−8kg.
Explanation:
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