Question

A mass of 10 kg is dropped from a height of 50 cm. Find its : () Kinetic energy
(ii) Velocity just as it reaches the ground. Does the velocity depend upon the
mass of the particle? Explain. [Take g = 10 ms-2]​

Answer 1

Given, mass of the object, m = 10 kg, Height, h = 50 cm = 0.5 m

(i) As potential energy is given by PE = mgh = 10 x 10 x 0.5 = 50 J

(ii) From law of conservation of energy, Total energy of the ball just before dropping = total energy of the ball just on touching the ground

⇒ KE + PE of ball just before dropping = KE of ball just on touching the ground = KE= 50 J

Plz mark as Brainliest

Answer 2

Answer:

Given mass of the object, m = 10 kg

Height h, = 50 cm = 0.5 m

1). As potential energy is given by PE = mgh = 10×10×0.5 = 50 j

2). From laws of conservation of energy,

Total energy of the ball just before dropping = total energy of the ball just on touching the ground

= KE + PE of ball just before dropping =

KE of ball just on touching the ground =

KE = 50j