Question

a mass of 10 Kg is placed on a sensitive physical balance 1000 kg mass is placed below 10 kg mass at a distance of 1 M how much additional marks will be required for balancing the physical balance

Answer 1

6.6 × 10^-8 kg additional mass is required for balancing the physical balance.

Explanation:

• When a 10 kg mass is weighed on a physical balance.
• Then the force of attraction of the body with the earth and compare it with the balance mass.
• But a 1000 kg mass placed at a distance of 1 m from the given mass, an additional gravitational force acts on the mass.

F = mg

F gravity = Gm1m2 / r^2

F = 6.6 × 10^-11 × 10 × 1000/1^2

F = 6.6×10^-7 N

Additional mass = 6.6 × 10^-7 / 10

= 6.6 × 10^-8 kg.

Thus 6.6 × 10^-8 kg additional mass is required for balancing the physical balance.

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