Question

A mass of 10 kg is placed on a smooth horizontal table. It is tied to a string which passes over a frictionless

pulley. On the other end of the string a mass m1 (5 kg) is tied. When the masses are in motion, the tension

on the string will be :

a) 98 N b) 49 N

c) 38.5 N d) 32.7 N​

Answer 1

Answer:d

Explanation:for mass on horizontal table ;T=10a

For mass tied on other end 5g -T=5a

Solve equation:5g =15a

g=3a

a=g/3

T=10*10/3