Question

A mass of 10 kg is suspended vertically by a rope from the roof. When a horizontal force is applied on the rope at some point, the rope deviated at an angle of 45 at the roof point. If the suspended mass is at equilibrium, the magnitude of the force applied is (g = 10 ms 2)

Answer 1

Given A mass of 10 kg is suspended vertically by a rope from the roof. When a horizontal force is applied on the rope at some point, the rope deviated at an angle of 45 at the roof point. If the suspended mass is at equilibrium, the magnitude of the force applied is (g = 10 ms 2)

We have the rope being deviated to 45 degree , so

 F/sin(180 - theeta) and Mg/sin(90 + theeta)

F/sin(180 - 45) = Mg/sin(90 + 45)

F/sin 45 = Mg/cos 45

F/1/√2 = Mg/1/√2

F = M x g

F = 10 x 10

F = 100 N