A mass of 100 g is attached to the end of a rubber string 49 cm long and having an area of cross section 20 mm2 . The string is whirled round, horizontally at a constant speed of 40 rps in a circle of radius 51 cm. Find the young's modulus of rubber. [
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Given that,
L = 49 cm
l = 51 - 49 = 2 cm
Cross sectional area a 20 mm2 = 0.2 cm2
m = 100 g
R = 51 cm
ω = 40 r.p.s = 80 π rad s-1
When the mass attached to the string is whirled, the length of the string increases under the effect of centrifugal force.
The centrifugal force F = mRω2
= 100 x 51 x (80 π)2
hope it helps you....
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