Question

A mass of 100 kg, moving in a frictionless surface at an initial velocity 10 m/s. Sand bag of 100 kg mass is placed on this moving cart. It's Final velocity is _____ m/s.​

Answer 1

Answer:

a)c

b)d

c)a

d)a

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Answer 2

Answer:

It's Final velocity is 5.55 m/s.

Explanation:

Step 1: Sand is dropping vertically in relation to the trolley since the hole is on the floor. Because there is no force acting in the horizontal plane, momentum is preserved in that direction.

According to the rule of conservation of momentum, absent an external force, the combined momentum of two or more bodies operating upon one another in an isolated system remains constant. As a result, momentum cannot be gained or lost.

Step 2:Let M equal the combined mass of a cart and a sandbag.

Initial velocity is v1, whereas ultimate velocity is v2 ( to be found)

Then $P_1=(M+m) v_1$ when the sand bag is empty the momentum is

$\mathrm{P}_2=(\mathrm{M}+0) \mathrm{v}_2$

Step 3:Momentum is conserved in horizontal direction so

$\begin{aligned}& \mathrm{P}_1=\mathrm{P}_2 \\& \Rightarrow=\mathrm{v}_2=\frac{(\mathrm{M}+\mathrm{m})}{\mathrm{M}} \mathrm{v}_1=\frac{100+100}{100} \times 10 \times \frac{5}{18}=5.55 \mathrm{~m} / \mathrm{s}\end{aligned}$

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