Question

A mass of 1000 kg having a speed of 10 M per second is brought to rest over a distance of 100 M. find the retardation and the retarding force?

Answer 1

Hello dear,

◆ Answer-
a) Retardation a = -0.5 m/s^2
b) Retarding force F = -500 N

◆ Explaination-
# Given-
m = 1000 kg
s = 100 m
u = 10 m/s
v = 0 m/s

# Solution-
Using Newton's 3rd Kinematic eqn -
v^2 = u^2 + 2as
0 = 10^2 + 2 × a × 100
a = -100/200
a = -0.5 m/s^2

Regarding force is calculated by -
F = ma
F = 1000 × (-0.5)
F = -500 N

Hope this helps you...

Answer 2

Explanation:

m=1000kg

s=100m

u=10m/s¹

v=0m/s¹

Newton's 3rd equation of motion

v²=u²+2as

0²=10²+2×a×100

0-100=2×a×100

-100/2×100=a

-100/200=a

-0.5=a

a= -0.5 m/s² -1

F=m×a

F=1000×(-0.5)

F= -500N -2