Question

A mass of 100kg is suspended from the centre of the rope at equilibrium the two halfs of the rope makes an angle 120° with each other . Find the tensor along the rope.



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Answer 1

Given: A mass of 100 kg is suspended from the centre of the rope at equilibrium.

To find: The tension along the rope.

Solution:

• Now we have given a mass of 100 kg which is suspended from the centre of the rope at equilibrium and also provided with the two halfs of the rope makes an angle 120° with each other.

• So after balancing the forces, we get:

               2T x cos (60°) = m x g

                2T x 1/2 = 100 x 9.8

                T = 980 N

Answer:

             So the tension in the rope is 980 N.