A mass of 10kg connected at the end of a rod the of negligible mass is rotating in a circle of radius 30cm with an angular velocity of 10 rad/s if the mass is brought to rest in 10sec by a break what is the magnitude of the torque applied
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Answer:
0.3
Explanation:
with help of first equation we Will find angular acceleration
torque = I × angular acceleration
and I = ml2/3
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