Question

a mass of 10kg is dropped from a height of 50 cm .find its
a) potential energy just befor dropping
b) kinatic energy just before touching the ground
c)velocity with witch it hits the ground
g=10ms-2​

Answer 1

Given, mass of the object, m = 10 kg , Height, h = 50 cm= 0.5 m

(i) As potential energy is given by PE = mgh

= 10 x 10 X 0.5 = 50 J

(ii) From law of conservation of energy,

total energy of the ball just before dropping = total energy of the ball just on touching the ground => KE + PE of ball just before dropping

= KE of ball just on touching the ground = KE= 50 J

(iii)As , we know KE = 50J

so, 1/2 m {{v}^{2}} = 50

{{v}^{2}} = 50 x 2/10 = 10

DEAR

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