Question

A mass of 10kg is dropped from a height of 50 m then find its kinetic energy

Answer 1

Answer:

m=10g

u=0m/s

a=g=9.8m/s

s=50

v=?

According to third equation of motion

2as=v^2-u^2

2x9.8x50=v^2-0^2

980=v^2

v^2=980

v=31.3049517 m/s

v=31.4m/s

K.E. =1/2mv^2

=1/2x10x31.4

=314/2

=157 joules

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