Question

A mass of 10kg is suspended vertically by a rope from the roof. When a horizontal force is applied on the rope at some point, the rope deviated at an angle of 45⁰ at the roof point.If the suspended mass is at equilibrium, the magnitude of the force applied is:
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Answer 1

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Given;−

A mass of 10kg is suspended vertically by a rope from the roof. When a horizontal force is applied on the rope at some point, the rope deviated at an angle of 45 at the roof point. If the suspended mass is at equilibrium, the magnitude of the force applied is (g=10m/s² )

We have the rope being deviated to 45°

so,

F/sin(180−θ) and Mg/sin(90+θ)

F/sin(180−45)=Mg/sin(90+45)

F/sin45=Mg/cos45

F/1/√2=Mg/1/√2

F=M×g

F=10×10

F=100N

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Answer 2

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