Question

A mass of 10kg moving at 5m/s collides head on woth mass 4kg moving at 2m/s in same direction. lf e=1/2 find their velocity after impact​

Answer 1

Explanation:

Let their velocities after the collision be v

1

and v

2

. As we know for elastic collision.

Relative velocity of approach = relative velocity of separation

10−4=v

2

−v

1

⇒6=v

2

−v

1

⇒v

1

=v

2

−6

Applying conservation of momentum,

10×10+5×4=10v

1

+5v

2

120=10v

1

+5v

2

120=10(v

2

−6)+5v

2

=15v

2

−60

15v

2

=180⇒v

2

=12cm/sec

v

1

=6cm/sec

Answer 2

Answer:

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