Question

A mass of 1kg is thrown up with a velocity of 100m/s after5seconds it explodes into two parts one part of mass 400g moves down with a velocity of 25m/s calculate tge velocity of otger part just after tgevexplosion

Answer 1

The velocity of the mass after 5 seconds (just before explosion) is

$v=u-gt\\ v=100-10(5)\\ v=50$

Since the momentum is conserved, the momentum before and after collision is the same.

Take the direction upwards as positive. The conservation of momentum says,

$1(50)=0.4(-25)+(1-0.4)v\\ 50=-10+0.6v\\ v=100$

The velocity of the other part after the explosion is $100 \;m/s$ upwards.

Answer 2

Answer:

correct answer is 100 m/s

Explanation:

Hope it will help you

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