Question

A mass of 2.0 kg is hung off a spring,which extends 2 cm Determine the energy stored in the spring

Answer 1

Answer:

Energy stored in a spring is 1/2 * k * x^2 where K is spring constant in N/m and x = extension in meters.

Here we have 1/2 * 100 * 9.81 N/m * 0.02^2 = 0.2 joules

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