Question

A mass of 2.0 kg stretches the spring by 2 cm. The
spring constant
of the spring is
a) 980 N/m
b. 98 N/m
c. 49 N/m
d. 9.8 N/m​

Answer 1

Answer:

⟹ (a) k = 980 N/m

Explanation:

Given :

Mass (m) = 2 kg

Spring stretched by (x) = 2cm = 0.02m

We know that

F = kx

F = mg

➞ F = 2 × 9.8

➞ F = 19.6 N

F = kx

⟹ k = F/x

⟹ k = 19.6/0.02

⟹ k = 980 N/m