a mass of 2.5 Kg is hung on a steel wire with increase 0.25 CM in its length determine the work done to pull the wire
Answers
Answered by
7
the work done will be = effort * displacement of effort
as affort = 2.5Kg
than length = 0.0025m
so total work done = 2.5*0.0025= 6.25*10power-4
as affort = 2.5Kg
than length = 0.0025m
so total work done = 2.5*0.0025= 6.25*10power-4
mickey4683:
pr solve kt sakte ho kya aap iss qution ko
please agar kr sakte ho to muhe send kr do please
i will try
ok
plese jaldi
Hello, I've done the calculation.. but the ans is 0.06125 not 0.03125...
ok send kr do
I've given the answer.. see...
ok
thanks
Answered by
7
Work done,W= Force×displacement =(2.5×9.8)×(0.0025) =0.06125J
Similar questions