Question

A mass of 2 kg is attached to a spring of force constant 200N/m . Find the time period?

Answer 1

Answer:

The equilibrium stretching is given by equating weight with spring force.

∴0.2×10=200×x

x=0.01m=1cm

When taken back to unstretched state, the sum of spring force and weight together is converted into spring force.

∴200×0.01+0.2×10=200×x

x=0.02m=2cm

The frequency is given by

f=

2π

1

m

k

=

2π

1

0.2

200

≈5.05Hz

Since frequency is independent of acceleration due to gravity, it will be same on moon. Hence, all options, A,B.C,D are correct.