Question

A mass of 2 kg is dropped from 10 m height.
Find out gain in K.E, of the block when it falls
through 5 m.
(1) 200 J
(2) 100 J
(3) 50 J
(4) 0J

Answer 1

Answer:

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Explanation:

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Answer 2

Given:

Mass (m) = 2 Kg

Initial distance ($h_{1}$) = 10 m

Final distance ( ) = 5 m

Initial kinetic enerygy ( ) = 0

To find:

Gain in kinetic energy(KE)

Solution:

As the body drops through 5 m,a part of the potential energy is converted to kinetic energy

• As per law of conservation of energy,

        $KE_{1}+ PE_{1} = KE_{2} + PE_{2}$

        0 + $mgh_{1}$  = $KE_{2}$ + $mgh_{2}$

        2×10×10 = $KE_{2}$ + 2*10*5

        $KE_{2}$ = 100 J

• Gain in kinetic energy (ΔKE) = $KE_{2} - KE_{1}$ = 100 - 0 = 100 J

• ΔKE = 100 J