A mass of 2 kg is dropped from 10 m height.
Find out gain in K.E, of the block when it falls
through 5 m.
(1) 200 J
(2) 100 J
(3) 50 J
(4) 0J
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Given:
Mass (m) = 2 Kg
Initial distance () = 10 m
Final distance ( ) = 5 m
Initial kinetic enerygy ( ) = 0
To find:
Gain in kinetic energy(KE)
Solution:
As the body drops through 5 m,a part of the potential energy is converted to kinetic energy
- As per law of conservation of energy,
0 + = +
2×10×10 = + 2*10*5
= 100 J
- Gain in kinetic energy (ΔKE) = = 100 - 0 = 100 J
- ΔKE = 100 J
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