Question

A mass of 2 kg is moving along a circular path of radius 1 m.if the mass moves with 300 revolutions per minute , it's K.E would be?​

Answer 1

Explanation:

Here,

Mass, m=5 kg,Radius,R=1 m

v=300 rpm=

60

300

rps=5 rps

The angular speed is given by

ω=2πv=2π×5=10πrads

−1

The linear speed is

v=ωR=(10πs

−1

)(1 m)=10πms

−1

Kinetic energy, K=

2

1

mv

2

K=

2

1

×(5 kg)(10πms

−1

)

2

=250π

2

J.