Question

A mass of 2 kg is suspended from a steel wire of length 1 meter to form a pendulum arrangement.if the mass is moved to one side and released from the horizontal position of wire then find the maximum extension of the length of the wire.the cross sectional area is 1mm^2

Answer 1

Answer:

A mass =2kg

It is suspended from a steel wire of length=l=1m

And cross-sectional area =10

−6

m

2

to form a perpendicular arrangement

If the mass is moved to one side and released from the horizontal position of wire then find the maximum extension in the length of the wire.

Solution

A mass of 2kg is suspended from a steel wire of length =1m to form a pendulum arrangement.

Of the mass is moved to one side and released from the horizontal position of wire then

Finding

g=10m/s

2

= gravitational force

Y

steel

=

L

Δl

10

−6

2×10

=

10

−6

ΔL

2×10×L

Y

steel

=

10

−6

2×10×1

×ΔL

2

60

×10

1

1×10

−

6=ΔL

ΔL=3×10

−

4m

ΔL=0.3mm

solution