Question

A mass of 2 kg lie on a plane making an angle 30 degree to the horizontal. resolve its weight along and perpendicular to the plane . asume g=10m/s

Answer 1

angle of inclination of the inclined plane is given as

$\theta = 30degree$

mass of the object is

$mass = 2 kg$

weight of the object will be perpendicular downwards

$W = 20 N$

now the angle of weight with the inclined plane will be 60 degree

so its component along the inclined plane is given as

$W_{along} = Wcos60$

$W_{along} = 20 cos60 = 10 N$

Now the component of weight perpendicular to plane will be

$W_{perpendicular} = 20sin60 = 10/sqrt3 N[tex]</p><p><strong>so the component of weight along the plane is 10 N and perpendicular to the plane is [tex]10\sqrt3$N

Answer 2

Answer:

the answer for this question is 17.32 N.