Question

a mass of 20 kg is hung off a spring which extends 2cm. determine the energy stored in the spring​

Answer 1

Explanation:

mass = 2.0 kg ; x = 2 cm = 0.02 m ; g = 9.8 m/s^2; E = ? joules

Solving for the spring constant k

F = kx

mg = kx

k = mg / x

k = 20 kg * 98 m/s^2 / 002 m = 980 N / m

Solving for the energy stored in the spring

E = 1/2 * k * x^2

E = 1/2 * 980 N / m * (002 m)^2

E = 0196 joules

The energy stored in the spring is 0196 joules.