Question

a mass of 200 Kg is placed on a rough inclined plane of 30 degree angle if coefficient of limiting friction is 1÷_/2 (1 divided by root 2) find the greatest 8 least forces in Newton acting parallel on a plane to keep the mass in equilibrium ​

Answer 1

HELLO MATE

Greatest Force - 1960N

Least Foce - 0N

Explanation:

R=mgcosθ

fmax= μR = μMG COSθ

So the greatest force requires to keep the body in equilibrium

Fmax = mgsinθ + fmax = mgsinθ +μmgcosθ

  = 200 x 9.8 {1/2 +1/√3 x √3/2} = 1960N

Fmin = mgsinθ -fmax

= mgsinθ - μmgcosθ

mg{sinθ - μcosθ}

=200 x 9.8{1/2 - 1/√3 x √3/2}

=200 x 9.8 x 0

=0N

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