Question

A mass of 20g is hung from the end of a light vertical spring and is set oscillating with an amplitude of 10cm .Its total energy is found to be 4J .If the mass is now replaced with a mass of 40g and it is again set oscillating with an amplitude of 10cm its total energy (in J) is now:​

Answer 1

Answer:

8×10  −3  J.

Explanation:

spring force F=kx

20×10  

−3

×10=k×2×10  

−2

 

k=10N/m

Energy stored in spring =  

2 1 kx  2  

=  2 1  ×10×(4×10  −2  )  2

 

=8×10  −3  J.

Answer 2

The total energy is 4J

Explanation:

We know that if the spring constant is k and amplitude of SHM is A then the total energy is given by

$E=\frac{1}{2}kA^2$

Thus, it is clear that the total energy depends upon the square of the amplitude

Since the spring constant in both the cases is same

And the amplitude is also the same

Therefore, the total energy will again be 4J

Hope this answer is helpful.

Know More:

Q: To double the total energy of an oscillating mass-spring system, by what factor must the amplitude increase?

Click Here: https://brainly.in/question/18363619

Q: A block of mass m is connected to one end of a spring of a spring constant k. the other end is fixed to a rigid support . the mass is released slowly so that the total energy of the system is then constituted by only the potential energy then d is the maximum extension in the spring . instead if the mass is released suddenly from the same initial position the maximum extension of the spring now is:

Click Here: https://brainly.in/question/12874721