Question

a mass of 25 kg is at rest.and a force of 100N IS APPLIED to it.what will be the velocity after 10s.what will be the distance covered during this time

Answer 1

Answer:

The mass of the body ,m=25kg

Force applied on it,F=100N

F =ma, where a is the acceleration

100 =25 a, the acceleration a= 4m/s^2

Initial velocity ,u=0

acceleration,a = 4m/s^2

time taken ,t =10s

final velocity ,v=u + at

V = 0+ 4x10 = 40m.

Distance travelled, S =ut + 1/2*a*t&2

S = 0 + (1/2)x 4 x 10 x10 =200m.