Physics, asked by rishikeshreddyouvxil, 1 year ago

a mass of 3.9kg suspended from a string of length/0.5 is at rest. another body of mass 0.1kg moving horizontally with a velocity 200m/s strikes and sticks to it. The tension in the string when it makes 60° with the vertical is (g=10m/s.s)

Answers

Answered by kishor5
1
3.9*0.5*sin 60/10*200
3.9*0.5*√3/2/10*200
is 33.77m/s^2.
Answered by INDIANROCKSTAR
3

Answer:

answer is 180Newton's

Similar questions