Question

A mass of 4 kg is hanging from a ceiling with the help of a massless string. If the tension in the string is 10 * k Newton. Find k (g = 10 m/s2) Clear Response​

Answer 1

Answer:

As the elevator is going upward with acceleration 29 so 2log block with focal 2×29 downward & 4log block with focal 4×29 downward as a prudes force.

⇒ weight + pruedo −T=ma

or 4g+2gT=4a ------ (1)

⇒T−(2g+9)=2a i.e. f=ma

 or T−3g=2a -------- (2)

(1)×1 (2)×2 we get 69−T−(2T−69)=+a+a

or 6g−3T+6g=0

T=312g=4g=40N

Answer 2

Answer:

According to formula .

F = m  x  g

10 K  = 40

k  = 4

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