Question

A mass of 4 kg rests on a horizontal plane the plane is gradually inclined. The block begins to move at an angle of 30° . what will be the acceleration of the block when the plane is inclined at an angle of 60°?​

Answer 1

Explanation:

We know that,

Mass m=4kg

angle θ=15

0

Now, the normal force is

N=mg

N=4×10

N=40N

Now, frictional force always opposes direction of motion

So,

F

f

=mgcosθ

μN=4×10×cos15

0

μ×40=40×0.96

μ=0.96

Hence, the friction is 0.96

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