Question

A mass of 4 kg rests on a horizontal plane. The plane is gradually inclined until at and angle = 15° with the horizontal, at which the mass just begins to slide. Obtain the expression for angle of friction. b) What is the coefficient of limiting friction in this case.​

Answer 1

Answer:

0.96

Explanation:

We know that,

Mass m=4kg

angle θ=15

0

Now, the normal force is

N=mg

N=4×10

N=40N

Now, frictional force always opposes direction of motion

So,

F

f

=mgcosθ

μN=4×10×cos15

0

μ×40=40×0.96

μ=0.96

Hence, the friction is 0.96

Answer 2

Answer:

Find the above attached as you requested.

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