Question

A mass of 4kg is suspended by a rope of length of 3m from a ceiling. A force of 30N is applied in the horizontal direction at the mid point of the rope .What is the angle of the rope makes with the vertical inequilibrium(g=10m/s^2)

Answer 1

first , find the resultant force (which will turn out to be 50) ..then consider a right angled triangle. hypotenuse is 50 . hence the other sides will be 40 and 30. find out tan ∅= 3/4 =37 degree is your answer