Question

A mass of 5 kg acted upon by a force of 1 n. Starting from rest how much is distance covered by mass in 20seconds​

Answer 1

Answer:

Using Newton's second law , F=ma, we get the acceleration to be 0.2m/s

2

.

now we know that s=ut+

2

1

at

2

u=0,t=10s,a=0.2m/s

2

∴s=

2

1

∗0.2∗10

2

=10m

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Answer 2

Using Newton's second law , F=ma, we get the acceleration to be 0.2m/s 2.

now we know that s=ut+ 21 at 2u=0,t=10s,a=0.2ms2∴s= 21 ∗0.2∗10 2=10m

Answered By Togoyoyo6