a mass of 5 kg is acted upon by a force of 1 N. starting from rest ,how much distance covered by the mass in 20 s
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Answered by
2
Answer:
m=5kg
F=1N
t=20s
F=ma
1=5a
5a=1
a=1/5m/s²
a= 0.2m/s²
s=ut+1/2at²
as u=0 (starting from rest)
s=1/2at²
=1/2x0.5x20x20
100m
Answered by
1
Answer:
- using newton second law
- f=ma we get the acceleration 0.2m/s
- now we know that
- s= ut+½ at 2
- u= 0 +10 a=0.2m/s²
- s= ½*0.210
- ans =10m
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