Question

A mass of 5 kg is dropped from a height of 1 M find its kinetic energy an
d velocity

Answer 1

Here h is given, we have to derive v.

Answer 2

The potential energy of the object will be equal to mgh

= 5 * 10 * 1

=50

Now when the body hits the ground

Potential energy at at start will be equal to kinetic energy in the last conserve mechanical energy

Therefore

mgh = 1/2mv²

10 * 1 = 1/2 * V2

= 2 √5