Question

.
A mass of 5 kg is placed on a horizontal rough
surface. Coefficient of friction between body and
surface is 0.5. The minimum horizontal force with
which the block can just able to move is


(1) 25 N
(2)√ (50) ²+ (25)² N
(3) 50N.
(4) 22.5N​

Answer 1

Answer:

minimum horizontal force= friction force

=u N ( where u is coefficient of friction and N is normal force)

= umg

= 0.5× 5×10

= 25

hope this will help you

Answer 2

Explanation:

skskkskskdkdkskkspamakxncndkdjcbdjdkxdldlapakapapaxbkvchdhajgdtajggdocapability , .⚡additive inverse of

- \frac{ 21}{22}−

22

21

1. Name of the student

2. AHA basket (in grade 8)

3. First Choice (in order of preference)

4. Second Choice ( in order of preference)

5. Third Choice (in order of preference)

6. If your new choice is different from your previous choice (in grade 8), then list down two valid reasons for opting out from the current choice. (In case you wish to continue with your current choice, write N/A)

7. How do you think you will add value to the new AHA basket? (In case you wish to continue with your current choice, write N/A)

capabilityBi Mansion