a mass of 5 kg is suspended by a rope of length 2m from a ceiling. a force of 50N in the horizontal direction is applied at the point P of the rope.
(i) what is the angle the rope makes with the vertical in equilibrium?
(ii) what is the tension in the rope?
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Explanation:
for the 5kg mass
it is in equilibrium
so
T2=mg
T2=50N
at point P
T1cosø=T2 .........(1 ] [ since in equilibrium
T1sinø=50N.........(2]['xxxx'x]
T1sinø/T1cosø=50/50
tanø=1
ø=tan^-1(1)
Ø=45°
T2=50N
T1sin45=50
T1/_/2=50
T1=50root2N
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