Physics, asked by harsimrankaursidhubr, 7 hours ago

A mass of 5 kg is suspended by a strong 10m long. A horizontal force is applied on the mass to pull it 5m from a vertical line through the point of suspension. Find the magnitude of the forces.

Answers

Answered by btanusree76

1

Answer:

there are three forces weight 5g, F and T acting on the mass at B.

Applying triangle law of vector

(F/AB)=(5g/OA)

F=5g×(AB/OA)

=(5×9.8)×(5/10)

=24.5 N

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