A mass of 5 kg moves with a velocity of 72 km/hr comes to stop after 5 seconds. find the force applied
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initial velocity (u)= 72km/hr
final velocity(v) = 0 km/hr
time taken (t) = 5sec
acceleration ( a) = v-u/t
= 0 -72/5
= -14.4 m/s^2
force = mass × acceleration
= 5× 14.4
= 72 N
final velocity(v) = 0 km/hr
time taken (t) = 5sec
acceleration ( a) = v-u/t
= 0 -72/5
= -14.4 m/s^2
force = mass × acceleration
= 5× 14.4
= 72 N
prithvirajk604:
This answer is fully wrong
how do u know
You have not changed the unit of initial velocity to m/sec
ok
Answered by
0
given
initial velocity,u=72km / hr ×5/18=20m/s
final velocity, v=0
time,t=5 sec
acc. = v-u/t = 0-20/5
= -20/5= -4m/sec^2
Force=mass ×acceleration
(5×-4) = -20N
initial velocity,u=72km / hr ×5/18=20m/s
final velocity, v=0
time,t=5 sec
acc. = v-u/t = 0-20/5
= -20/5= -4m/sec^2
Force=mass ×acceleration
(5×-4) = -20N
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