Question

a mass of 50 kg was moving with a velocity 400m/s. a force of 40,000N is applied on the mass and its velocity is reduced to 50m/s after some time . what is the distance travelled by the mass during this period ?


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Answer 1

Answer:

Mass = 50 kg

u = 400 m/s

V = 50 m/s

F = 40000 N

t = unknown

Distance travelled in time (t) = ?

Acceleration (a) = F/m

= 40000/50

= 800 m/s²

Again,

Acceleration = change of velocity/t

or, t = change of velocity/a

or, t = 350/800 sec

★ Distance travelled:

s = ut – (½)at²

= 400 × (350/800) – (½) × 800 × (350/800)²

= 175 – 76.5

= 98.5 m

Answer 2

Answer:

Mass= 50kg

V = 50 m/s

F= 40000n

T=?

Distance a traveling in time t=

Acceleration = a=f/m

=40000/ 50 = 800 m/s2

Again Acceleration = change of velocity /t

Or - change of velocity /a = 350/ 800 sec

Distance travelled : s= ut_ ( 1 /2) at2

= 400* ( 350/ 800)_(1/2) 800.( 350/800)2

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= 175-76.5 = 98.5 m