Question

A mass of 50 kg was moving with a velocity 400m/s. A force of 40000 N is applied on the mass and its velocity is reduce to 50 m/s after some time. what is the distance traveled by the mass during this period ​

Answer 1

Answer:

98.5m is the right answer for this question.

Answer 2

Mass = 50 kg

u = 400 m/s

v= 50 m/s

F = 40000 N

t = unknown

Distance travelled in time t =?

Acceleration = a = F/m = 40000/50 = 800 m/s²

Again, acceleration a = change of velocity /t

or, t = change of velocity/a = 350/800 sec

★ Distance travelled: s = ut – (1/2)a t²

= 400 * (350/800) – (1/2) 800. (350/800)²

= 175 – 76.5 = 98.5 m