A mass of 50 kilogram is suspended from end of a wire of length 100 cm and diameter 2mm. Calculate the elongation of wire if y = 12.5x10000000000 Nm-2
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Answer:
1.278 x 10-³ m
Explanation:
y=fl/pi r² delta L
m = 50kg
l = 100cm = 1m
d=2mm
r=1mm=0.01m
50*10*7/22*(0.01)²*delta l = 12.5*10¹⁰
*calculations*
delta l = 1.278*10-³ m
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