Question

A mass of 5kg moving horizontally with a speed of 2m/s is acted by a force of 20N perpendicularly . What will be the velocity after 2 sec??​

Answer 1

Answer:

√68 m/s

Explanation:

Acceleration along vertical direction

a = F/m

= 20 N / (5 kg)

= 4 N / kg

= 4 m/s²

Velocity along vertical after 2 seconds is

v = u + at

= 0 m/s + (4 m/s² × 2 s)

= 8 m/s

Velocity along horizontal after 2 seconds is still 2 m/s

Magnitude of net velocity after 2 s is then

V = √(2² + 8²) m/s

= √(4 + 64) m/s

= √68 m/s