A mass of 5kg moving horizontally with a speed of 2m/s is acted by a force of 20N perpendicularly . What will be the velocity after 2 sec??
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Answer:
√68 m/s
Explanation:
Acceleration along vertical direction
a = F/m
= 20 N / (5 kg)
= 4 N / kg
= 4 m/s²
Velocity along vertical after 2 seconds is
v = u + at
= 0 m/s + (4 m/s² × 2 s)
= 8 m/s
Velocity along horizontal after 2 seconds is still 2 m/s
Magnitude of net velocity after 2 s is then
V = √(2² + 8²) m/s
= √(4 + 64) m/s
= √68 m/s
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