Question

A mass of 6 kg is suspended by a rope of length 2m from ceiling. A force

of 120 N is applied in the horizontal direction at the mid-point of the rope. What is

the angle made by the rope with the vertical?

(Take g= 10 m/s2​

Answer 1

Answer:

For horizontal equilibrium-

T

3

=T

1

sinθ

For vertical equilibrium-

T

2

=T

1

cosθ

Taking ratios-

T

2

T

3

=tanθ

And for equilibrium of body T

2

=6kgwt=6×10=60N

⟹tanθ=

6

5

or θ=tan

−1

6

5