Question

A mass of 60g is hanging from one end of a metre scale pivoted at 40cm mark. An insect of mass 100g starts to crawl along the scale from the other end. It takes 6 seconds for the scale to attain equilibrium. Calculate the speed of the insect. Neglect the mass of the scale.

Answer 1

Answer:

50 g

Explanation:

As 100g is balanced at fulcrum it will have a perpendicular distance of 40cm from itself and mass m will have 40−20=20cm distance.

Here moment of forces are equal that is balance each other.

Hence m×(40−20)=100×(50−40)

⇒m=100/2=50g.

Hence value of m is 50g.

Answer 2

Answer:

This is the answer of your question.