Question

A mass of 63g potassium manganate KMnO4, is needed for the complete oxidation of 23g of ethanol C2H5OH under acidic conditions.
How many moles of ethyanol can be completely oxidised by one mole of potassium under these conditions.
(a) 0.37
(b) 0.80
(c) 1.00
(d) 1.25

Answer 1

Answer:

sorry I dont know this answer

Answer 2

Answer:

d

Explanation:

1 mol of KMnO4=158g

KMnO4  :  C2H5OH

63g        :  23g

158g       :  x

cross multiply (direct proportion)

x=57.58g

now calculate how many moles are in 57.58g of ethanol

1mol  :  46g

x        :  57.68g

x=1.25mol